5(y^2+7)=20

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Solution for 5(y^2+7)=20 equation: 



5(y^2+7)=20

We move all terms to the left:

5(y^2+7)-(20)=0

We multiply parentheses

5y^2+35-20=0

We add all the numbers together, and all the variables

5y^2+15=0

a = 5; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·5·15
Δ = -300
Delta is less than zero, so there is no solution for the equation

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